The structures of XeF_2 and XeF_4 respectivel | vedclass

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(A) For $XeF_2$: The central atom $Xe$ has $8$ valence electrons. It forms $2$ bonds with $F$ atoms and has $3$ lone pairs. The steric number is $2 +

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linear and square planar

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(A) For $XeF_2$: The central atom $Xe$ has $8$ valence electrons. It forms $2$ bonds with $F$ atoms and has $3$ lone pairs. The steric number is $2 + 3 = 5$,which corresponds to $sp^3d$ hybridization. Due to the presence of $3$ lone pairs in the equatorial positions,the shape is linear.For $XeF_4$: The central atom $Xe$ has $8$ valence electrons. It forms $4$ bonds with $F$ atoms and has $2$ lone pairs. The steric number is $4 + 2 = 6$,which corresponds to $sp^3d^2$ hybridization. Due to the presence of $2$ lone pairs in the axial positions,the shape is square planar.Thus,$XeF_2$ is linear and $XeF_4$ is square planar.

The structures of $XeF_2$ and $XeF_4$ respectively are

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