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(A) The problem asks for the number of ways to arrange $4$ students who have secured the same rank.Since there are $4$ distinct students,the number of

Vedclass · Accepted Answer

$24$

Vedclass · Answer

(A) The problem asks for the number of ways to arrange $4$ students who have secured the same rank.Since there are $4$ distinct students,the number of ways to arrange them in a sequence (or rank order) is given by the number of permutations of $4$ distinct objects.The number of permutations of $n$ distinct objects is given by $n!$.Here,$n = 4$.Therefore,the total number of arrangements $= 4! = 4 	imes 3 	imes 2 	imes 1 = 24$.Thus,the teacher needs $24$ bits of paper to write down all possible arrangements.

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