The sum of $n$ terms of an $A.P.$ is given by $S_{n} = 2n^{2} + 5n$. Then,the $n^{th}$ term of the $A.P.$ $T_{n} = \dots$

  • A
    $4n + 3$
  • B
    $4n - 3$
  • C
    $3n + 4$
  • D
    $3n - 4$

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For the $A.P.$ $-2, -4, -6, \ldots,$ the common difference $d = \ldots$

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