The sum of all possible numbers that can be formed by using the digits $2, 3, 5, 7$ without repetition of digits is

  • A
    $17 \times \frac{10^4-1}{9}$
  • B
    $33 \times 34 \times 101$
  • C
    $6 \times \frac{10^3-1}{9}$
  • D
    $33 \times 35 \times 1001$

Explore More

Similar Questions

Let $x$ and $y$ be two $2$-digit numbers such that $y$ is obtained by reversing the digits of $x$. Suppose they also satisfy $x^2-y^2=m^2$ for some positive integer $m$. The value of $x+y+m$ is

$(2n + 1) (2n + 3) (2n + 5) \dots (4n - 1)$ is equal to :

Difficult
View Solution

The number of different $5$-digit numbers greater than $50000$ that can be formed using the digits $0, 1, 2, 3, 4, 5, 6, 7$,such that the sum of their first and last digits is not more than $8$,is:

The number of integers greater than $6000$ that can be formed using the digits $3, 5, 6, 7,$ and $8$ without repetition is:

The digit in the unit place of the number $(183!) + (3^{183})$ is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo