The sum of the first $n$ terms of the series $\frac{1}{2 \cdot 5} + \frac{1}{5 \cdot 8} + \frac{1}{8 \cdot 11} + \ldots$ is

  • A
    $\frac{3n}{2(3n+2)}$
  • B
    $\frac{3n}{3n+2}$
  • C
    $\frac{n}{2(3n+2)}$
  • D
    $\frac{n}{3n+2}$

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