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(C) For $K_3[Cr(C_2O_4)_3]$: Oxidation state $= +3$,Coordination number $= 6$,Sum $= 3 + 6 = 9$For $[Cr(CO)_6]$: Oxidation state $= 0$,Coordination nu

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$K_2[PtCl_6]$

Vedclass · Answer

(C) For $K_3[Cr(C_2O_4)_3]$: Oxidation state $= +3$,Coordination number $= 6$,Sum $= 3 + 6 = 9$For $[Cr(CO)_6]$: Oxidation state $= 0$,Coordination number $= 6$,Sum $= 0 + 6 = 6$For $K_2[PtCl_6]$: Oxidation state $= +4$,Coordination number $= 6$,Sum $= 4 + 6 = 10$For $K_4[Fe(CN)_6]$: Oxidation state $= +2$,Coordination number $= 6$,Sum $= 2 + 6 = 8$Thus,the sum is maximum for $K_2[PtCl_6]$.

The sum of the oxidation state and the coordination number of the central metal atom is maximum for which of the following complexes?

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