The sum of three numbers is 2. The 1^{text{st | vedclass

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(B) Let the $2^{	ext{nd}}$ number be $x$.According to the problem:$1^{	ext{st}}$ number $= \frac{x}{2}$$3^{	ext{rd}}$ number $= \frac{x}{4}$The sum

Vedclass · Accepted Answer

$\frac{8}{7}$

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(B) Let the $2^{	ext{nd}}$ number be $x$.According to the problem:$1^{	ext{st}}$ number $= \frac{x}{2}$$3^{	ext{rd}}$ number $= \frac{x}{4}$The sum of the three numbers is $2$,so:$\frac{x}{2} + x + \frac{x}{4} = 2$To solve for $x$,find a common denominator,which is $4$:$\frac{2x + 4x + x}{4} = 2$$\frac{7x}{4} = 2$$7x = 8$$x = \frac{8}{7}$Thus,the $2^{	ext{nd}}$ number is $\frac{8}{7}$.

The sum of three numbers is $2$. The $1^{\text{st}}$ number is $\frac{1}{2}$ times the $2^{\text{nd}}$ number and the $3^{\text{rd}}$ number is $\frac{1}{4}$ times the $2^{\text{nd}}$ number. The $2^{\text{nd}}$ number is

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