The surface tension of a liquid is $5 \, N/m$. If a thin film of the area $0.02 \, m^2$ is formed on a loop,then its surface energy will be

  • A
    $5 \times 10^2 \, J$
  • B
    $2.5 \times 10^{-2} \, J$
  • C
    $2 \times 10^{-1} \, J$
  • D
    $5 \times 10^{-1} \, J$

Explore More

Similar Questions

The change in surface energy when a big spherical drop of radius $R$ is split into $n$ spherical droplets of radius $r$ is ($T=$ surface tension).

If $T$ is the surface tension,the amount of work done in blowing a soap bubble from a diameter $d$ to diameter $D$ is

The work done in blowing a soap bubble of radius $0.2 \, m$,given that the surface tension of the soap solution is $60 \times 10^{-3} \, N/m$,is:

Difficult
View Solution

One thousand small water drops of equal radii combine to form a big drop. The ratio of final surface energy to the total initial surface energy is

The radius of a soap bubble is $r$. The surface tension of the soap solution is $T$. Keeping the temperature constant,the radius of the soap bubble is doubled. The energy necessary for this process will be: (in $\pi r^2 T$)

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo