(B) The surface tension of the soap solution is given as $T = 0.03 \,N/m$. The surface area of the soap bubble is $A = 40 \,cm^2 = 40 \times 10^{-4} \

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(B) The surface tension of the soap solution is given as $T = 0.03 \,N/m$. The surface area of the soap bubble is $A = 40 \,cm^2 = 40 \times 10^{-4} \,m^2$. $A$ soap bubble has two surfaces (inner and outer), so the change in surface area is $\Delta A = 2 \times A$. The work done $W$ in blowing the soap bubble is given by the formula: $W = T \times \Delta A_{total} = T \times 2 \times A$. Substituting the values: $W = 0.03 \times 2 \times 40 \times 10^{-4} \,J$. $W = 0.06 \times 40 \times 10^{-4} \,J$. $W = 2.4 \times 10^{-4} \,J$.

Class 11 Physics Fluid Mechanics and Surface Tension Surface Energy

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The surface tension of soap solution is $0.03 \,N/m$. The work done in blowing to form a soap bubble of surface area $40 \,cm^2$ (in $J$) is:

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A
$1.2 \times 10^{-4}$
B
$2.4 \times 10^{-4}$
C
$12 \times 10^{-4}$
D
$24 \times 10^{-4}$

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Fluid Mechanics and Surface Tension

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Surface Energy

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The surface tension of soap solution is $0.03 \,N/m$. The work done in blowing to form a soap bubble of surface area $40 \,cm^2$ (in $J$) is:

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