The temperature dependence of the rate constant $k$ is expressed as $k = A e^{-E_a / RT}$. When a plot between $\log k$ and $1/T$ is plotted,we get the graph as shown. What is the value of the slope in the graph?

  • A
    $\frac{E_a}{RT}$
  • B
    $-\frac{E_a}{2.303R}$
  • C
    $-\frac{E_a}{2.303RT} \log A$
  • D
    $-\frac{E_a}{2.303} \frac{R}{T}$

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The temperature-dependent equation for the rate constant is written as:

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For an endothermic reaction $X \rightarrow Y$,the activation energies for the forward and backward reactions are $E_f$ and $E_b$ respectively. Then,in general:

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