The temperature of 5 moles of a gas at consta | vedclass

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(B) Given: Number of moles $n = 5$, initial temperature $T_1 = 100^{\circ} C$, final temperature $T_2 = 120^{\circ} C$, change in internal energy $\De

Vedclass · Accepted Answer

$4$

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(B) Given: Number of moles $n = 5$, initial temperature $T_1 = 100^{\circ} C$, final temperature $T_2 = 120^{\circ} C$, change in internal energy $\Delta U = 80 \,J$.The change in temperature is $\Delta T = T_2 - T_1 = 120^{\circ} C - 100^{\circ} C = 20 \,K$ (since the change in temperature is the same in Celsius and Kelvin).The change in internal energy for a gas at constant volume is given by $\Delta U = C_V \Delta T$, where $C_V$ is the total heat capacity at constant volume.Therefore, $C_V = \frac{\Delta U}{\Delta T} = \frac{80 \,J}{20 \,K} = 4 \,J/K$.

The temperature of $5$ moles of a gas at constant volume is changed from $100^{\circ} C$ to $120^{\circ} C$. The change in internal energy is $80 \,J$. The total heat capacity of the gas at constant volume in $J/K$ is:

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