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(D) Given temperatures are $t_{1} = 20^{\circ}C \pm 0.5^{\circ}C$ and $t_{2} = 50^{\circ}C \pm 0.5^{\circ}C$.To find the temperature difference $\Delt

Vedclass · Accepted Answer

$30^{\circ}C \pm 1^{\circ}C$

Vedclass · Answer

(D) Given temperatures are $t_{1} = 20^{\circ}C \pm 0.5^{\circ}C$ and $t_{2} = 50^{\circ}C \pm 0.5^{\circ}C$.To find the temperature difference $\Delta t = t_{2} - t_{1}$,we subtract the values:$\Delta t = (50 - 20)^{\circ}C = 30^{\circ}C$.When subtracting two quantities,the absolute errors are added.Therefore,the error in the difference is $\Delta(\Delta t) = \Delta t_{1} + \Delta t_{2} = 0.5^{\circ}C + 0.5^{\circ}C = 1.0^{\circ}C$.Thus,the temperature difference is $30^{\circ}C \pm 1^{\circ}C$.

The temperatures of two bodies measured by a thermometer are $t_{1} = 20^{\circ}C \pm 0.5^{\circ}C$ and $t_{2} = 50^{\circ}C \pm 0.5^{\circ}C$. Calculate the temperature difference and the error therein.

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