The time taken by a force of $2 \ N$ to produce a change of momentum of $0.4 \ kg \ m \ s^{-1}$ in a body is: (in $s$)

The variation of momentum $(p)$ with time $(t)$ for one of the bodies in a two-body collision is shown in the figure. The instantaneous force is maximum corresponding to which point?

$A$ force $\vec{F_1}$ of magnitude $4 \ N$ acts on an object of mass $1 \ kg$ at the origin in a direction $30^{\circ}$ above the positive $x$-axis. $A$ second force $\vec{F_2}$ of magnitude $4 \ N$ acts on the same object in the direction of the positive $y$-axis. The magnitude of the acceleration of the object is nearly: (in $m \ s^{-2}$)

$A$ body of mass $2\, kg$ travels according to the law $x = at + bt^2 + ct^3$,where $a = 3\, m/s$,$b = 4\, m/s^2$,and $c = 5\, m/s^3$. The force acting on the body at $t = 2\, s$ is ......... $N$.

If a bullet of mass $5 \,g$ moving with velocity $100 \,m/s$ penetrates a wooden block up to $6 \,cm$,then the average force imposed by the bullet on the block is ........... $N$.

The position vector of a particle related to time $t$ is given by $\overrightarrow{r} = (10t \hat{i} + 15t^2 \hat{j} + 7 \hat{k}) \text{ m}$. The direction of the net force experienced by the particle is: