The torque on a bar magnet due to the earth's | vedclass

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(A) The torque $	au$ acting on a bar magnet of magnetic moment $M$ placed in an external magnetic field $B$ is given by the formula $	au = MB \sin \

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Perpendicular to the field of the earth

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(A) The torque $	au$ acting on a bar magnet of magnetic moment $M$ placed in an external magnetic field $B$ is given by the formula $	au = MB \sin 	heta$,where $	heta$ is the angle between the magnetic axis and the magnetic field.For the earth's magnetic field,the torque is $	au = M B_H \sin 	heta$,where $B_H$ is the horizontal component of the earth's magnetic field.The torque $	au$ is maximum when $\sin 	heta$ is maximum,which occurs at $	heta = 90^{\circ}$.Therefore,the torque is maximum when the axis of the magnet is perpendicular to the earth's magnetic field.

The torque on a bar magnet due to the earth's magnetic field is maximum when the axis of the magnet is

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