The total energy of a particle executing simp | vedclass

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Question

(C) The total energy $(E)$ of a particle executing simple harmonic motion is given by the sum of its kinetic energy $(K)$ and potential energy $(U)$.$

Vedclass · Accepted Answer

independent of $x$

Vedclass · Answer

(C) The total energy $(E)$ of a particle executing simple harmonic motion is given by the sum of its kinetic energy $(K)$ and potential energy $(U)$.$E = K + U = \frac{1}{2} m \omega^2 A^2$,where $m$ is the mass,$\omega$ is the angular frequency,and $A$ is the amplitude.Since $m$,$\omega$,and $A$ are constants for a given simple harmonic motion,the total energy $E$ remains constant throughout the motion.Therefore,the total energy is independent of the displacement $x$ from the equilibrium position.Thus,option $(c)$ is correct.

The total energy of a particle executing simple harmonic motion is

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