The total intensity of the Earth's magnetic f | vedclass

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Question

(B) The total intensity of the Earth's magnetic field at a magnetic latitude $\lambda$ is given by the formula: $B = B_{eq} \sqrt{1 + 3 \sin^2 \lambda

Vedclass · Accepted Answer

$\sqrt{52}$ $units$

Vedclass · Answer

(B) The total intensity of the Earth's magnetic field at a magnetic latitude $\lambda$ is given by the formula: $B = B_{eq} \sqrt{1 + 3 \sin^2 \lambda}$,where $B_{eq}$ is the intensity at the magnetic equator.Given $B_{eq} = 5$ $units$ and $\lambda = 37^{\circ}$.Using $\sin 37^{\circ} \approx 0.6$,we have $\sin^2 37^{\circ} = (0.6)^2 = 0.36$.Substituting these values into the formula:$B = 5 \sqrt{1 + 3(0.36)}$$B = 5 \sqrt{1 + 1.08}$$B = 5 \sqrt{2.08}$$B = 5 \sqrt{\frac{208}{100}} = 5 	imes \frac{\sqrt{208}}{10} = \frac{\sqrt{208}}{2} = \sqrt{\frac{208}{4}} = \sqrt{52}$ $units$.

The total intensity of the Earth's magnetic field at the magnetic equator is $5$ $units$. Its value at a magnetic latitude of $37^{\circ}$ is equal to:

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