The total number of chiral molecules formed f | vedclass

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(C) Ozonolysis of the given molecule $P$ involves the cleavage of all $C=C$ double bonds.Upon performing ozonolysis $(O_3, Zn / H_2O)$,the molecule $P

Vedclass · Accepted Answer

$2$

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(C) Ozonolysis of the given molecule $P$ involves the cleavage of all $C=C$ double bonds.Upon performing ozonolysis $(O_3, Zn / H_2O)$,the molecule $P$ breaks into several smaller carbonyl compounds.By analyzing the structure of the products formed:$1$. $CH_3CH_2CHO$ (Propanal) - Achiral$2$. $CH_3C(=O)C(OH)(CH_3)C(=O)CH_3$ - Achiral (due to plane of symmetry)$3$. $CH_3C(=O)C(OH)(CH_3)CHO$ - Chiral (contains a chiral center)$4$. $CH_3C(=O)C(OH)(CH_3)C(=O)CH_3$ - Achiral$5$. $CH_3C(=O)C(OH)(CH_3)CHO$ - Chiral$6$. $CH_3C(=O)C(OH)(CH_3)C(=O)CH_3$ - Achiral$7$. $CH_3CHO$ (Ethanal) - AchiralCounting the chiral molecules,we find there are $2$ such molecules.

The total number of chiral molecules formed from one molecule of $P$ on complete ozonolysis $(O_3, Zn / H_2O)$ is. . . . . . .

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