The total number of electrons in all bonding | vedclass

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(B) The total number of electrons in $O_{2}^{2-}$ is $8 + 8 + 2 = 18$.The molecular orbital configuration of $O_{2}^{2-}$ is $\sigma 1s^2, \sigma^* 1s

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$10$

Vedclass · Answer

(B) The total number of electrons in $O_{2}^{2-}$ is $8 + 8 + 2 = 18$.The molecular orbital configuration of $O_{2}^{2-}$ is $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2, \pi 2p_y^2, \pi^* 2p_x^2, \pi^* 2p_y^2$.The bonding molecular orbitals are $\sigma 1s, \sigma 2s, \sigma 2p_z, \pi 2p_x, 	ext{ and } \pi 2p_y$.The number of electrons in these bonding orbitals are $2, 2, 2, 2, 	ext{ and } 2$ respectively.Total bonding electrons = $2 + 2 + 2 + 2 + 2 = 10$.

The total number of electrons in all bonding molecular orbitals of $O_{2}^{2-}$ is $....$ (Round off to the Nearest Integer).

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