The total number of monohalogenated organic products (including stereoisomers) formed in the following reaction is:
$A$ (simplest optically active alkene) $\xrightarrow[(ii) X_2/\Delta ]{(i) H_2/Ni/\Delta }$

$A$ (organic compound) $+ O_2 \to X + Y + Z$. Compound $(A)$ in pure form does not give a precipitate with $AgNO_3$ solution. $A$ mixture containing $70\%$ of $(A)$ and $30\%$ of ether is used as an anaesthetic. Compound $(X)$ and $(Y)$ are oxides while $(Z)$ is a pungent smelling gas. $(X)$ is a neutral oxide which turns cobalt chloride paper pink. Compound $(Y)$ turns lime water milky and produces an acidic solution with water. Compounds $(A), (X), (Y)$ and $(Z)$ respectively will be:

Assertion : Alkylbenzene is not prepared by Friedel-Crafts alkylation of benzene.
Reason : Alkyl halides are less reactive than acyl halides.

When $but-3-en-2-ol$ reacts with aqueous $HBr$,the product formed is:

Match the reactants in Column-$I$ with their products in Column-$II$.

Column-$I$ (Reactants)	Column-$II$ (Products)
$A$. $H_2C=CH_2 + Br_2 \xrightarrow{CCl_4}$	$i$. $CH_3CH_2CH_2Br$
$B$. $CH_3CH=CH_2 + HI \rightarrow$	$ii$. $BrCH_2-CH_2Br$
$C$. $C_6H_5N_2^+X^- + KI \rightarrow$	$iii$. $CH_3CHICH_3$
$D$. $CH_3CH=CH_2 + HBr \xrightarrow{peroxide}$	$iv$. $C_6H_5I$

What happens when
$(i)$ $n$-butyl chloride is treated with alcoholic $KOH$.
$(ii)$ bromobenzene is treated with $Mg$ in the presence of dry ether.
$(iii)$ chlorobenzene is subjected to hydrolysis.
$(iv)$ ethyl chloride is treated with aqueous $KOH$.
$(v)$ methyl bromide is treated with sodium in the presence of dry ether.
$(vi)$ methyl chloride is treated with $KCN$?