The total number of sigma and pi bonds in 2-o | vedclass

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Question

(C) The structural formula of $2$-oxohex-$4$-ynoic acid is $CH_3-C \equiv C-CH_2-C(=O)-COOH$. To find the total number of bonds,we count the $\sigma$

Vedclass · Accepted Answer

$18$

Vedclass · Answer

(C) The structural formula of $2$-oxohex-$4$-ynoic acid is $CH_3-C \equiv C-CH_2-C(=O)-COOH$. To find the total number of bonds,we count the $\sigma$ and $\pi$ bonds: $1.$ $\sigma$ bonds: - $C-H$ bonds: $3$ (from $CH_3$) + $2$ (from $CH_2$) + $1$ (from $COOH$) = $6$ - $C-C$ single bonds: $3$ - $C \equiv C$ triple bond: $1$ $\sigma$ - $C=O$ double bonds: $2$ $\sigma$ - $C-O$ single bond: $1$ - $O-H$ single bond: $1$ Total $\sigma$ bonds = $6 + 3 + 1 + 2 + 1 + 1 = 14$. $2.$ $\pi$ bonds: - $C \equiv C$ triple bond: $2$ $\pi$ - $C=O$ double bonds: $2$ $\pi$ Total $\pi$ bonds = $2 + 2 = 4$. Total number of bonds = $\sigma + \pi = 14 + 4 = 18$.

The total number of $\sigma$ and $\pi$ bonds in $2$-oxohex-$4$-ynoic acid is . . . . . . .

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