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(B) Step $1$: Reaction of $CH_3COCl$ with $(CH_3)_2Cd$ gives acetone $(P)$ as $CH_3COCH_3$. Step $2$: The reaction of acetone $(CH_3COCH_3)$ and aceta

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$4$

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(B) Step $1$: Reaction of $CH_3COCl$ with $(CH_3)_2Cd$ gives acetone $(P)$ as $CH_3COCH_3$. Step $2$: The reaction of acetone $(CH_3COCH_3)$ and acetaldehyde $(CH_3CHO)$ in the presence of $NaOH$ and $\Delta$ is a cross-aldol condensation. Since both carbonyl compounds possess $\alpha$-hydrogens,they undergo self-aldol and cross-aldol condensation. The possible products are: $1$. Self-aldol of acetaldehyde: $CH_3CH=CHCHO$ $2$. Self-aldol of acetone: $(CH_3)_2C=CHCOCH_3$ $3$. Cross-aldol ($CH_3CHO$ as nucleophile): $CH_3CH=C(CH_3)CHO$ $4$. Cross-aldol (acetone as nucleophile): $(CH_3)_2C=CHCHO$ Thus,the total number of structural products formed is $4$.

The total number of structural products formed in the following reaction sequence is $CH_3COCl \xrightarrow{i) (CH_3)_2Cd} (P)$; $(P) + CH_3CHO \xrightarrow{ii) NaOH (aq.), \Delta} ?$

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