The transconductance of a triode amplifier is $2.5 \, \text{mS}$ (milli-mho) and its plate resistance is $20 \, \text{k}\Omega$. If the voltage amplification is $10$, find the load resistance in $\text{k}\Omega$.

In a triode,the cathode,grid,and plate are at potentials of $0 \, V$,$-2 \, V$,and $80 \, V$ respectively. Electrons are emitted from the cathode with an initial kinetic energy of $3 \, eV$. What is the energy of the electron when it reaches the plate in $eV$?

In the grid circuit of a triode,a signal $E = 2\sqrt{2} \cos(\omega t)$ is applied. If the amplification factor $\mu = 14$ and the plate resistance $r_p = 10\,k\Omega$,then the root mean square $(RMS)$ current flowing through the load resistance $R_L = 12\,k\Omega$ will be.......$mA$.

The slope of the plate characteristic of a vacuum tube diode for a certain operating point on the curve is $10^{-3} \text{ mA/V}$. The plate resistance of the diode and its nature are respectively:

The value of plate current $I_P$ in the given circuit diagram will be in $mA$.

In a triode,${g_m} = 2 \times 10^{-3} \, \Omega^{-1}$,$\mu = 42$,and the resistance load $R_L = 50 \, \text{k}\Omega$. The voltage amplification obtained from this triode will be: