The translational kinetic energy of the molecules of a gas at absolute temperature $T$ can be doubled by

  • A
    increasing $T$ to $4T$
  • B
    increasing $T$ to $\sqrt{2}T$
  • C
    decreasing $T$ to $T/2$
  • D
    increasing $T$ to $2T$

Explore More

Similar Questions

If the average translational kinetic energy of a molecule in a gas is equal to the kinetic energy of an electron accelerating from rest through $10 \,V$, then the temperature of the gas molecule is (Boltzmann constant $= 1.38 \times 10^{-23} \,JK^{-1}$)

Obtain an expression for the momentum of a gas transferred to the walls of a container in time $\Delta t$.

Estimate the average thermal energy of a helium atom at:
$(i)$ room temperature $(27^{\circ} C)$,
$(ii)$ the temperature on the surface of the Sun $(6000\; K)$,
$(iii)$ the temperature of $10$ million kelvin (the typical core temperature in the case of a star).

Increase in temperature of a gas filled in a container would lead to

$A$ container of volume $10^{-3} \ m^3$ contains $3.0 \times 10^{22}$ gas molecules,each having a mass of $5.3 \times 10^{-26} \ kg$. If the $rms$ speed of the molecules is $400 \ m/s$,calculate the pressure exerted by the gas.

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo