The truth table for the given logic circuit i | vedclass

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(B) The given logic circuit consists of two $NOT$ gates, two $AND$ gates, and one $OR$ gate. The output $Y$ is given by the Boolean expression: $Y = \

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(B) The given logic circuit consists of two $NOT$ gates, two $AND$ gates, and one $OR$ gate. The output $Y$ is given by the Boolean expression: $Y = \bar{A} \cdot B + A \cdot \bar{B}$. This is the expression for an $XOR$ gate. The truth table is constructed as follows:$A$$B$$Y$$0$$0$$0$$0$$1$$1$$1$$0$$1$$1$$1$$0$Comparing this with the given options, Option $B$ represents the correct truth table.

The truth table for the given logic circuit is

Similar Questions

The output from a $NAND$ gate having inputs $A$ and $B$ given below will be:

For a two-input $AND$ gate,the four entries are shown in the truth table. Identify the correct ones out of these ($A, B =$ input,$Y =$ output).
Entry $A$ $B$ $Y$
$1$ $0$ $1$ $0$
$2$ $1$ $0$ $0$
$3$ $1$ $1$ $1$
$4$ $0$ $0$ $1$

For the following circuit and given inputs $A$ and $B$, choose the correct option for output $Y$.

Logic gates are constructed by

In the following circuit,the output $Y$ for all possible inputs $A$ and $B$ is expressed by the truth table.

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