The two electrons in the K shell will differ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The $K$ shell corresponds to the principal quantum number $n = 1$.For $n = 1$,the only possible value for the azimuthal quantum number $l$ is $0$

Vedclass · Accepted Answer

Spin quantum number

Vedclass · Answer

(D) The $K$ shell corresponds to the principal quantum number $n = 1$.For $n = 1$,the only possible value for the azimuthal quantum number $l$ is $0$ ($s$-orbital).For $l = 0$,the only possible value for the magnetic quantum number $m_l$ is $0$.According to the Pauli exclusion principle,no two electrons in an atom can have the same set of all four quantum numbers.Therefore,the two electrons in the $1s$ orbital must differ in their spin quantum number ($m_s = +1/2$ and $m_s = -1/2$).

The two electrons in the $K$ shell will differ in which of the following quantum numbers?

Similar Questions

The radial part of the wave function is determined by which quantum numbers?

Not considering the electronic spin,the degeneracy of the second excited state $(n=3)$ of $H$ atom is $9$,while the degeneracy of the second excited state of $H^{-}$ is

In $Sr$ $(Z=38)$, the number of electrons with $l=0$ is $x$, and the number of electrons with $l=2$ is $y$. The value of $(x-y)$ is equal to:
($l=$ Azimuthal quantum number)

$4s^2$ is the configuration of the outermost orbit of an element. Its atomic number would be $:-$

What is the maximum number of electrons that can be accommodated in $d$ and $f$ orbitals,respectively?

Vedclass Test Series

Exam Paper Generator

Online Exam Module