The two ends of a rod of length $L$ and a uniform cross-sectional area $A$ are kept at two temperatures $T_1$ and $T_2$ $(T_1 > T_2)$. The rate of heat transfer,$\frac{dQ}{dt}$,through the rod in a steady state is given by:

  • A
    $\frac{k(T_1 - T_2)}{LA}$
  • B
    $kLA(T_1 - T_2)$
  • C
    $\frac{kA(T_1 - T_2)}{L}$
  • D
    $\frac{kL(T_1 - T_2)}{A}$

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