The two thigh bones (femurs),each of cross-se | vedclass

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(A) Given,mass of the body,$m = 50 \,kg$; acceleration due to gravity,$g = 10 \,m/s^2$.Total cross-sectional area,$A = 2 	imes$ area of each thigh bo

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$2.5 	imes 10^5$

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(A) Given,mass of the body,$m = 50 \,kg$; acceleration due to gravity,$g = 10 \,m/s^2$.Total cross-sectional area,$A = 2 	imes$ area of each thigh bone = $2 	imes 10 \,cm^2 = 20 \,cm^2$.Converting area to $m^2$: $A = 20 	imes 10^{-4} \,m^2 = 2 	imes 10^{-3} \,m^2$.The force exerted is the weight of the body: $F = mg = 50 	imes 10 = 500 \,N$.Pressure $P$ is defined as force per unit area: $P = F/A$.$P = 500 / (2 	imes 10^{-3}) = 250 	imes 10^3 = 2.5 	imes 10^5 \,N/m^2$.

The two thigh bones (femurs),each of cross-sectional area $10 \,cm^2$,support the upper part of a person of mass $50 \,kg$. The average pressure sustained by the femurs is ........... $N/m^2$.

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