The two thigh bones (femurs),each of cross-se | vedclass

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Question

(A) Given,mass of the body,$m = 50 \, kg$.Acceleration due to gravity,$g = 10 \, m/s^2$.Total area of cross-section of two thigh bones,$A = 2 	imes 1

Vedclass · Accepted Answer

$2.5 	imes 10^5$

Vedclass · Answer

(A) Given,mass of the body,$m = 50 \, kg$.Acceleration due to gravity,$g = 10 \, m/s^2$.Total area of cross-section of two thigh bones,$A = 2 	imes 10 \, cm^2 = 20 \, cm^2$.Converting area to $m^2$: $A = 20 	imes 10^{-4} \, m^2 = 2 	imes 10^{-3} \, m^2$.The force exerted by the upper part of the body is equal to its weight,$F = mg = 50 	imes 10 = 500 \, N$.Pressure $P = \frac{F}{A} = \frac{500}{2 	imes 10^{-3}} = 250 	imes 10^3 = 2.5 	imes 10^5 \, N/m^2$.

The two thigh bones (femurs),each of cross-sectional area $10 \, cm^2$,support the upper part of a person of mass $50 \, kg$. The average pressure sustained by the femurs is ............. $N/m^2$.

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