The two wires A and B of equal cross-section | vedclass

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(C) The formula for elongation is $\Delta L = \frac{FL}{AY}$.Since the wires are joined together and kept under tension, the force $F$ applied to both

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$1.21$

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(C) The formula for elongation is $\Delta L = \frac{FL}{AY}$.Since the wires are joined together and kept under tension, the force $F$ applied to both wires is the same.Given that the cross-sectional area $A$ and the elongation $\Delta L$ are also equal for both wires, we have:$\frac{L_A}{Y_A} = \frac{L_B}{Y_B} \Rightarrow \frac{L_B}{L_A} = \frac{Y_B}{Y_A}$.Given the ratio of Young's modulus $\frac{Y_A}{Y_B} = \frac{20}{11}$, it follows that $\frac{Y_B}{Y_A} = \frac{11}{20}$.Substituting the given length $L_A = 2.2	ext{ m}$:$L_B = L_A 	imes \frac{11}{20} = 2.2 	imes \frac{11}{20} = \frac{24.2}{20} = 1.21	ext{ m}$.

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