The type of oxide formed by the element among | vedclass

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Question

(A) The atomic radii of the given elements decrease across a period and increase down a group. Comparing the elements $Li$,$Na$,$Be$,$Mg$,$B$,and $Al$

Vedclass · Accepted Answer

$A_2O_3$

Vedclass · Answer

(A) The atomic radii of the given elements decrease across a period and increase down a group. Comparing the elements $Li$,$Na$,$Be$,$Mg$,$B$,and $Al$: $B$ (Boron) is in the $2^{nd}$ period and group $13$. $Be$ (Beryllium) is in the $2^{nd}$ period and group $2$. $Li$ (Lithium) is in the $2^{nd}$ period and group $1$. Across the $2^{nd}$ period,the atomic radius decreases from $Li$ to $Be$ to $B$. Thus,$B$ has the smallest atomic radius among the given elements. Boron $(B)$ belongs to group $13$,which has a valence of $+3$. Therefore,it forms an oxide of the type $B_2O_3$,which corresponds to the general formula $A_2O_3$.

The type of oxide formed by the element among $Li$,$Na$,$Be$,$Mg$,$B$,and $Al$ that has the least atomic radius is $:$

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