The uncertainty in momentum of an electron is $1 \times 10^{-5} \ kg \ m/s$. The uncertainty in its position will be $(h = 6.63 \times 10^{-34} \ Js)$.

In Heisenberg's uncertainty equation $\Delta x \times \Delta p \ge \frac{h}{4\pi}$,$\Delta p$ stands for:

The uncertainty principle was enunciated by

If the uncertainty in velocity of electron $(\Delta v)$ is $0.1 \ m/s$,the uncertainty in its position $(\Delta x)$ is (given: $m_e = 9.1 \times 10^{-31} \ kg$)

Calculate the mass of an elementary particle,which is accelerated to twice the velocity of light with the precision $\pm 1 \%$,and has $1.05 \times 10^{-13} \ m$ uncertainty in position. $(h = 6.6 \times 10^{-34} \ kg \ m^2 \ s^{-1})$

The uncertainties in the velocities of two particles,$A$ and $B$ are $0.05 \ ms^{-1}$ and $0.02 \ ms^{-1}$ respectively. The mass of $B$ is five times that of the mass of $A$. What is the ratio of uncertainties $\frac{\Delta x_A}{\Delta x_B}$ in their positions?