(B) In a $ccp$ structure,there are $8$ corners and $6$ face centres. Number of $A$ atoms initially at corners $= 8 \times \frac{1}{8} = 1$. Since $2$

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(B) In a $ccp$ structure,there are $8$ corners and $6$ face centres. Number of $A$ atoms initially at corners $= 8 \times \frac{1}{8} = 1$. Since $2$ $A$ atoms are missing from the corners,the number of $A$ atoms remaining $= 1 - (2 \times \frac{1}{8}) = 1 - 0.25 = 0.75 = \frac{3}{4}$. Number of $B$ atoms at face centres $= 6 \times \frac{1}{2} = 3$. The ratio of $A : B = \frac{3}{4} : 3 = 3 : 12 = 1 : 4$. Therefore,the composition of the alloy is $AB_4$.

Class 12 Chemistry Solid State Crystal structure and Coordination number

Medium

The unit cell of a binary compound of $A$ and $B$ metals has a $ccp$ structure with $A$ atoms occupying the corners and $B$ atoms occupying the centres of each face of the cubic unit cell. If during the crystallisation of this alloy,two $A$ atoms are missing from the unit cell,the overall composition per unit cell is:

A
$AB_6$
B
$AB_4$
C
$AB_8$
D
$A_6B_{24}$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Chemistry Questions

Chapter

Solid State

Subtopic

Crystal structure and Coordination number

An ionic compound has unit cells consisting of $A$ ions at the corners of a cube and $B$ ions on the centres of the faces of the cube. The empirical formula of this compound is

Medium

View Solution

If the radius ratio is in the range of $0.732 - 1.000$,then the coordination number will be

Medium

View Solution

In a face-centered cubic lattice of $X$ and $Y$ atoms,$X$ atoms are present at the corners while $Y$ atoms are at the face centers. If two atoms of $X$ are missing from the corners,what is the formula of the compound?

Medium

View Solution

What are the coordination numbers of $bcc$,$scc$,and $fcc$ respectively?

Easy

View Solution

The ratio of cationic radius to anionic radius in an ionic crystal is greater than $0.732$. Its coordination number is

Medium

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

Similar Questions

An ionic compound has unit cells consisting of $A$ ions at the corners of a cube and $B$ ions on the centres of the faces of the cube. The empirical formula of this compound is

If the radius ratio is in the range of $0.732 - 1.000$,then the coordination number will be

In a face-centered cubic lattice of $X$ and $Y$ atoms,$X$ atoms are present at the corners while $Y$ atoms are at the face centers. If two atoms of $X$ are missing from the corners,what is the formula of the compound?

What are the coordination numbers of $bcc$,$scc$,and $fcc$ respectively?

The ratio of cationic radius to anionic radius in an ionic crystal is greater than $0.732$. Its coordination number is

Vedclass Test Series

Exam Paper Generator

Online Exam Module