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Question

(A) The induced dipole moment $\vec{p}$ is proportional to the applied electric field $\vec{E_0}$,given by the relation $\vec{p} = \alpha \vec{E_0}$,w

Vedclass · Accepted Answer

$C^2 m N^{-1}$

Vedclass · Answer

(A) The induced dipole moment $\vec{p}$ is proportional to the applied electric field $\vec{E_0}$,given by the relation $\vec{p} = \alpha \vec{E_0}$,where $\alpha$ is the polarizability of the molecule.From this,we can express polarizability as $\alpha = \frac{\vec{p}}{\vec{E_0}}$.The unit of dipole moment $\vec{p}$ is Coulomb-meter $(C \cdot m)$.The unit of electric field $\vec{E_0}$ is Newton per Coulomb ($N/C$ or $N \cdot C^{-1}$).Therefore,the unit of $\alpha = \frac{C \cdot m}{N \cdot C^{-1}} = \frac{C^2 \cdot m}{N} = C^2 \cdot m \cdot N^{-1}$.

The unit of polarizability of the molecule is . . . . . . .

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