(B) For the reaction $2 A \rightleftharpoons B + C$,the reaction quotient $Q_{c}$ is given by:$Q_{c} = \frac{[ B ][ C ]}{[ A ]^{2}}$Given $[ A ] = [ B

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(B) For the reaction $2 A \rightleftharpoons B + C$,the reaction quotient $Q_{c}$ is given by:$Q_{c} = \frac{[ B ][ C ]}{[ A ]^{2}}$Given $[ A ] = [ B ] = [ C ] = 3 \times 10^{-4} \ M$,we calculate $Q_{c}$:$Q_{c} = \frac{(3 \times 10^{-4})(3 \times 10^{-4})}{(3 \times 10^{-4})^{2}} = 1$Since $Q_{c} = 1$ and $K_{c} = 2 \times 10^{-3}$,we observe that $Q_{c} > K_{c}$.Therefore,the reaction will proceed in the reverse direction to attain equilibrium.

Class 11 Chemistry 6-1.Equilibrium (Chemical Equilibrium)Law of equilibrium and Equilibrium constant

Medium

The value of $K_{c}$ for the reaction $2 A \rightleftharpoons B + C$ is $2 \times 10^{-3}$. At a given time,the composition of the reaction mixture is $[ A ] = [ B ] = [ C ] = 3 \times 10^{-4} \ M$. In which direction will the reaction proceed?

A
Forward direction
B
Reverse direction
C
The reaction is at equilibrium
D
No reaction occurs

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Chemistry Questions

Chapter

6-1.Equilibrium (Chemical Equilibrium)

Subtopic

Law of equilibrium and Equilibrium constant

The equilibrium constant $K_C$ of the reaction,$2 A \rightleftharpoons B + C$ is $0.5$ at $25^{\circ} C$. The reaction will proceed in the backward direction,when concentrations $[A], [B]$ and $[C]$ are,respectively:

MediumKVPY 2014

View Solution

Write the uses of equilibrium constant.

Medium

View Solution

Concentration of a gas is expressed in which of the following terms in the calculation of the equilibrium constant?

Easy

View Solution

For the reaction $3A + 2B \rightleftharpoons C$,the expression for the equilibrium constant $K_c$ is:

Medium

View Solution

The equilibrium constant expression for the reaction $P_{4(s)} + 5O_{2(g)} \rightleftharpoons P_4O_{10(s)}$ is:

DifficultTS EAMCET 2021

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

The value of $K_{c}$ for the reaction $2 A \rightleftharpoons B + C$ is $2 \times 10^{-3}$. At a given time,the composition of the reaction mixture is $[ A ] = [ B ] = [ C ] = 3 \times 10^{-4} \ M$. In which direction will the reaction proceed?

Similar Questions

The equilibrium constant $K_C$ of the reaction,$2 A \rightleftharpoons B + C$ is $0.5$ at $25^{\circ} C$. The reaction will proceed in the backward direction,when concentrations $[A], [B]$ and $[C]$ are,respectively:

Write the uses of equilibrium constant.

Concentration of a gas is expressed in which of the following terms in the calculation of the equilibrium constant?

For the reaction $3A + 2B \rightleftharpoons C$,the expression for the equilibrium constant $K_c$ is:

The equilibrium constant expression for the reaction $P_{4(s)} + 5O_{2(g)} \rightleftharpoons P_4O_{10(s)}$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module