The value of frac{2 frac{1}{3}-1 frac{2}{11}} | vedclass

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Question

(A) First,simplify the numerator: $2 \frac{1}{3} - 1 \frac{2}{11} = \frac{7}{3} - \frac{13}{11} = \frac{77 - 39}{33} = \frac{38}{33}$.Next,simplify th

Vedclass · Accepted Answer

$\frac{38}{109}$

Vedclass · Answer

(A) First,simplify the numerator: $2 \frac{1}{3} - 1 \frac{2}{11} = \frac{7}{3} - \frac{13}{11} = \frac{77 - 39}{33} = \frac{38}{33}$.Next,simplify the denominator: $3 + \frac{1}{3 + \frac{1}{3 + \frac{1}{3}}} = 3 + \frac{1}{3 + \frac{1}{\frac{10}{3}}} = 3 + \frac{1}{3 + \frac{3}{10}} = 3 + \frac{1}{\frac{33}{10}} = 3 + \frac{10}{33} = \frac{99 + 10}{33} = \frac{109}{33}$.Finally,divide the numerator by the denominator: $\frac{38/33}{109/33} = \frac{38}{33} 	imes \frac{33}{109} = \frac{38}{109}$.

The value of $\frac{2 \frac{1}{3}-1 \frac{2}{11}}{3+\frac{1}{3+\frac{1}{3+\frac{1}{3}}}}$ is

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