The value of $\sqrt{\frac{0.16}{0.4}}$ is

  • A
    $0.02$
  • B
    $0.2$
  • C
    $0.632$
  • D
    None of these

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$\left(\frac{2+\sqrt{3}}{2-\sqrt{3}}+\frac{2-\sqrt{3}}{2+\sqrt{3}}+\frac{\sqrt{3}-1}{\sqrt{3}+1}\right)$ simplifies to

If $\sqrt{\left(1+\frac{27}{169}\right)}=1+\frac{x}{13},$ then $x$ equals

$\sqrt{0.01+\sqrt{0.0064}}=?$

If $\sqrt{x} + \sqrt{441} = 0.02$,then the value of $x$ is

$(2 \sqrt{392}-21)+(\sqrt{8}-7)^{2}=(?)^{2}$

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