The value of sin 600^circ cos 330^circ + cos | vedclass

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(A) We use the reduction formulas for trigonometric functions:$\sin 600^\circ = \sin(360^\circ + 240^\circ) = \sin 240^\circ = \sin(180^\circ + 60^\ci

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$-1$

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(A) We use the reduction formulas for trigonometric functions:$\sin 600^\circ = \sin(360^\circ + 240^\circ) = \sin 240^\circ = \sin(180^\circ + 60^\circ) = -\sin 60^\circ = -\frac{\sqrt{3}}{2}$$\cos 330^\circ = \cos(360^\circ - 30^\circ) = \cos 30^\circ = \frac{\sqrt{3}}{2}$$\cos 120^\circ = \cos(180^\circ - 60^\circ) = -\cos 60^\circ = -\frac{1}{2}$$\sin 150^\circ = \sin(180^\circ - 30^\circ) = \sin 30^\circ = \frac{1}{2}$Substituting these values into the expression:$\sin 600^\circ \cos 330^\circ + \cos 120^\circ \sin 150^\circ = \left(-\frac{\sqrt{3}}{2}\right) \left(\frac{\sqrt{3}}{2}\right) + \left(-\frac{1}{2}\right) \left(\frac{1}{2}\right)$$= -\frac{3}{4} - \frac{1}{4} = -\frac{4}{4} = -1$.

The value of $\sin 600^\circ \cos 330^\circ + \cos 120^\circ \sin 150^\circ$ is

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