The value of frac{cos 2 theta}{1-sin 2 theta} | vedclass

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(B) We know that $\cos 2	heta = \sin \left(\frac{\pi}{2} - 2	hetaight)$ and $\sin 2	heta = \cos \left(\frac{\pi}{2} - 2	hetaight)$.Substitutin

Vedclass · Accepted Answer

$\cot \left(\frac{\pi}{4}-	hetaight)$

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(B) We know that $\cos 2	heta = \sin \left(\frac{\pi}{2} - 2	hetaight)$ and $\sin 2	heta = \cos \left(\frac{\pi}{2} - 2	hetaight)$.Substituting these into the expression:$\frac{\cos 2	heta}{1 - \sin 2	heta} = \frac{\sin \left(\frac{\pi}{2} - 2	hetaight)}{1 - \cos \left(\frac{\pi}{2} - 2	hetaight)}$Using the double angle identities $\sin 2A = 2 \sin A \cos A$ and $1 - \cos 2A = 2 \sin^2 A$,where $A = \frac{\pi}{4} - 	heta$:$= \frac{2 \sin \left(\frac{\pi}{4} - 	hetaight) \cos \left(\frac{\pi}{4} - 	hetaight)}{2 \sin^2 \left(\frac{\pi}{4} - 	hetaight)}$$= \frac{\cos \left(\frac{\pi}{4} - 	hetaight)}{\sin \left(\frac{\pi}{4} - 	hetaight)}$$= \cot \left(\frac{\pi}{4} - 	hetaight)$.

The value of $\frac{\cos 2 \theta}{1-\sin 2 \theta}=$

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