The value of (sec theta + operatorname{cosec} | vedclass

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(A) We know that $\sec 	heta = \frac{1}{\cos 	heta}$ and $\operatorname{cosec} 	heta = \frac{1}{\sin 	heta}$.For $	heta = 45^{\circ}$, we have $\

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$2$

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(A) We know that $\sec 	heta = \frac{1}{\cos 	heta}$ and $\operatorname{cosec} 	heta = \frac{1}{\sin 	heta}$.For $	heta = 45^{\circ}$, we have $\cos 45^{\circ} = \frac{1}{\sqrt{2}}$ and $\sin 45^{\circ} = \frac{1}{\sqrt{2}}$.Therefore, $\sec 45^{\circ} = \sqrt{2}$ and $\operatorname{cosec} 45^{\circ} = \sqrt{2}$.Substituting these values into the expression: $\sec 45^{\circ} + \operatorname{cosec} 45^{\circ} = \sqrt{2} + \sqrt{2} = 2 \sqrt{2}$.

The value of $(\sec \theta + \operatorname{cosec} \theta)$ when $\theta = 45^{\circ}$ is: (in $\sqrt{2}$)

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