The value of g at a particular point is 9.8,m | vedclass

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(C) The acceleration due to gravity at a point at a distance $r$ from the center of the Earth is given by the formula $g = \frac{GM}{r^2}$,where $G$ i

Vedclass · Accepted Answer

$9.8$

Vedclass · Answer

(C) The acceleration due to gravity at a point at a distance $r$ from the center of the Earth is given by the formula $g = \frac{GM}{r^2}$,where $G$ is the universal gravitational constant,$M$ is the mass of the Earth,and $r$ is the distance of the point from the center of the Earth.According to the problem,the mass $M$ of the Earth remains constant.The distance $r$ of the point from the center of the Earth also remains constant as stated in the problem.Since $G$,$M$,and $r$ all remain unchanged,the value of $g$ at that specific point remains $9.8\,m/s^2$.

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