The value of g at a place decreases by 2%. Th | vedclass

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(A) The pressure $P$ exerted by the mercury column in a barometer is given by the formula $P = h \rho g$,where $h$ is the height of the mercury column

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Increases by $2\%$

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(A) The pressure $P$ exerted by the mercury column in a barometer is given by the formula $P = h \rho g$,where $h$ is the height of the mercury column,$\rho$ is the density of mercury,and $g$ is the acceleration due to gravity.Since the atmospheric pressure $P$ remains constant and the density $\rho$ of mercury is constant,we have $h \propto \frac{1}{g}$.Taking the logarithmic derivative,we get $\frac{\Delta h}{h} = -\frac{\Delta g}{g}$.Given that $g$ decreases by $2\%$,we have $\frac{\Delta g}{g} = -0.02$.Substituting this into the equation,$\frac{\Delta h}{h} = -(-0.02) = 0.02$.Therefore,the height $h$ increases by $2\%$.

The value of $g$ at a place decreases by $2\%$. The barometric height of mercury:

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