The value of theta between 0^circ and 360^cir | vedclass

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(D) Given the equation: $	an 	heta + \frac{1}{\sqrt{3}} = 0$ This implies: $	an 	heta = -\frac{1}{\sqrt{3}}$ Since $	an 	heta$ is negative,$	he

Vedclass · Accepted Answer

$	heta = 150^\circ$ and $330^\circ$

Vedclass · Answer

(D) Given the equation: $	an 	heta + \frac{1}{\sqrt{3}} = 0$ This implies: $	an 	heta = -\frac{1}{\sqrt{3}}$ Since $	an 	heta$ is negative,$	heta$ must lie in the second or fourth quadrant. We know that $	an(30^\circ) = \frac{1}{\sqrt{3}}$. In the second quadrant,$	heta = 180^\circ - 30^\circ = 150^\circ$. In the fourth quadrant,$	heta = 360^\circ - 30^\circ = 330^\circ$. Thus,the values of $	heta$ are $150^\circ$ and $330^\circ$.

The value of $\theta$ between $0^\circ$ and $360^\circ$ satisfying the equation $\tan \theta + \frac{1}{\sqrt{3}} = 0$ is equal to:

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