The value of a machine depreciates at the rat | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The present value of the machine is $P = Rs. 29644.032$.The rate of depreciation is $r = 12\%$ per annum.The time period is $n = 3$ years.The form

Vedclass · Accepted Answer

$43500$

Vedclass · Answer

(B) The present value of the machine is $P = Rs. 29644.032$.The rate of depreciation is $r = 12\%$ per annum.The time period is $n = 3$ years.The formula for the depreciated value is given by $V = P_0 	imes (1 - \frac{r}{100})^n$,where $P_0$ is the initial purchase price.To find the purchase price $P_0$,we rearrange the formula:$P_0 = \frac{V}{(1 - \frac{r}{100})^n}$Substituting the given values:$P_0 = \frac{29644.032}{(1 - \frac{12}{100})^3}$$P_0 = \frac{29644.032}{(0.88)^3}$$P_0 = \frac{29644.032}{0.681472}$$P_0 = 43500$Therefore,the purchase price of the machine was $Rs. 43500$.

The value of a machine depreciates at the rate of $12\%$ per annum. It was purchased $3$ years ago. Its present value is $Rs. 29644.032$. What was the purchase price (in $Rs.$) of the machine?

Similar Questions

What will be the amount (in ₹) received on $25000$ at the rate of $20 \%$ per annum compounded yearly for $4$ years?

If $Rs. 3000$ amounts to $Rs. 4320$ at compound interest in a certain time,then what will $Rs. 3000$ amount to in half of that time (in $Rs.$)?

$A$ sum of ₹ $3,200$ invested at $10 \%$ per annum compounded quarterly amounts to ₹ $3,362$. Compute the time period (in years).

Find the compound interest on $Rs. 32000$ at $20 \%$ per annum for $1$ year,compounded half-yearly (in $Rs.$).

Find the compound interest (in ₹) on ₹ $15625$ for $9$ months at $16 \%$ per annum compounded quarterly.

Vedclass Test Series

Exam Paper Generator

Online Exam Module