The value of the angle of dip is zero at the | vedclass

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(C) The angle of dip (or magnetic inclination) $\delta$ is defined by the relation $	an \delta = \frac{V}{H}$,where $V$ is the vertical component of

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The value of $V$ is zero

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(C) The angle of dip (or magnetic inclination) $\delta$ is defined by the relation $	an \delta = \frac{V}{H}$,where $V$ is the vertical component of the Earth's magnetic field and $H$ is the horizontal component.At the magnetic equator,the Earth's magnetic field lines are parallel to the surface of the Earth.Therefore,the vertical component $V$ of the Earth's magnetic field is zero at the magnetic equator.Substituting $V = 0$ into the formula,we get $	an \delta = \frac{0}{H} = 0$,which implies $\delta = 0^\circ$.Thus,the correct option is $C$.

The value of the angle of dip is zero at the magnetic equator because on it:

Similar Questions

If the magnetic declination at a place is known to be $15^{\circ} \, E$,and a compass needle points as shown in the figure,then the geographic north is represented by which numbered direction?

Let $V$ and $H$ be the vertical and horizontal components of the Earth's magnetic field at any point on Earth. Near the North Pole:

If $\theta_1$ and $\theta_2$ are the apparent angles of dip observed in two vertical planes at right angles to each other,then the true angle of dip $\theta$ is given by:

The correct relation is:
$B_H$ = Horizontal component of earth's magnetic field; $B_V$ = Vertical component of earth's magnetic field and $B$ = Total intensity of earth's magnetic field.

At the magnetic north pole of the earth, the value of the horizontal component of the earth's magnetic field and the angle of dip are, respectively:

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