The values of bond enthalpy of $H_2$,$Cl_2$ and $HCl$ are $104$,$58$ and $103 \ kcal/mol$ respectively. Find the enthalpy of formation of $HCl_{(g)}$. Reaction: $\frac{1}{2}H_{2(g)} + \frac{1}{2}Cl_{2(g)} \to HCl_{(g)}$

  • A
    $22 \ kcal/mol$
  • B
    $-22 \ kcal/mol$
  • C
    $59 \ kcal/mol$
  • D
    $-59 \ kcal/mol$

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