The value of the discriminant of a quadratic | vedclass

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Question

(C) The given quadratic equation is $kx^{2} - 4x - 4 = 0$. Comparing this with the standard form $ax^{2} + bx + c = 0$,we get $a = k$,$b = -4$,and $c

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(C) The given quadratic equation is $kx^{2} - 4x - 4 = 0$. Comparing this with the standard form $ax^{2} + bx + c = 0$,we get $a = k$,$b = -4$,and $c = -4$.The discriminant $D$ is given by the formula $D = b^{2} - 4ac$.Given that $D = 64$,we substitute the values into the formula:$(-4)^{2} - 4(k)(-4) = 64$$16 + 16k = 64$$16k = 64 - 16$$16k = 48$$k = \frac{48}{16}$$k = 3$

The value of the discriminant of a quadratic equation $kx^{2} - 4x - 4 = 0$ is $64$,then $k = \dots$

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