The value of equivalent capacitance of the co | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $1$. The three capacitors at the bottom left,each of capacitance $C$,are in parallel. Their equivalent capacitance is $C_{p1} = C + C + C = 3C$.$2

Vedclass · Accepted Answer

$3\,C$

Vedclass · Answer

(B) $1$. The three capacitors at the bottom left,each of capacitance $C$,are in parallel. Their equivalent capacitance is $C_{p1} = C + C + C = 3C$.$2$. This $3C$ is in series with the capacitor of $3C$ above it. Their equivalent capacitance is $C_{s1} = \frac{3C 	imes 3C}{3C + 3C} = \frac{9C^2}{6C} = 1.5C = \frac{3C}{2}$.$3$. This $\frac{3C}{2}$ is in parallel with the capacitor of $\frac{3C}{2}$ next to it. Their equivalent capacitance is $C_{p2} = \frac{3C}{2} + \frac{3C}{2} = 3C$.$4$. This $3C$ is in series with the top capacitor of $3C$. Their equivalent capacitance is $C_{s2} = \frac{3C 	imes 3C}{3C + 3C} = 1.5C = \frac{3C}{2}$.$5$. Finally,this $\frac{3C}{2}$ is in parallel with the capacitor of $\frac{3C}{2}$ connected directly between $P$ and $Q$. The total equivalent capacitance is $C_{eq} = \frac{3C}{2} + \frac{3C}{2} = 3C$.

The value of equivalent capacitance of the combination shown in the figure between the points $P$ and $Q$ is

Similar Questions

In the given capacitor network,$C_1 = 10\,\mu F$,$C_2 = 5\,\mu F$,and $C_3 = 4\,\mu F$. What is the resultant capacitance between $A$ and $B$ in $\mu F$?

In the given circuit,a charge of $+80 \mu C$ is given to the upper plate of a $4 \mu F$ capacitor. At steady state,the charge on the upper plate of the $3 \mu F$ capacitor is (in $\mu C$)

The equivalent capacitance between $A$ and $B$ in the given figure is

Three condensers of capacities $C_{1}, C_{2}, C_{3}$ are connected in series with a source of e.m.f. $V$. The potentials across the three condensers are in the ratio of

In the given circuit,what is the potential difference across the $6\, \mu F$ capacitor in volts?

Vedclass Test Series

Exam Paper Generator

Online Exam Module