The values of the crystal field stabilization energies for a high spin $d^{6}$ metal ion in octahedral and tetrahedral fields,respectively,are :

  • A
    $-0.4 \Delta_{o}$ and $-0.27 \Delta_{t}$
  • B
    $-1.6 \Delta_{o}$ and $-0.4 \Delta_{t}$
  • C
    $-0.4 \Delta_{o}$ and $-0.6 \Delta_{t}$
  • D
    $-2.4 \Delta_{o}$ and $-0.6 \Delta_{t}$

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Which of the following correctly represents the order of ligands in the spectrochemical series?

The color of $[Ti(H_2O)_6]^{3+}$ is due to:

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How many of the following ligands are stronger than $H_2O$? $S^{2-}$,$Br^{-}$,$C_2O_4^{2-}$,$CN^{-}$,$en$,$NH_3$,$CO$,$OH^{-}$

Given below are two statements: Statement $I$: Each electron in $e_g$ orbitals destabilizes the orbitals by $+0.6\Delta_o$ and each electron in the $t_{2g}$ orbitals stabilizes the orbitals by $-0.4\Delta_o$ in an octahedral field on the basis of crystal field theory. Statement $II$: All the $d$-orbitals of the transition metals have the same energy in their free atomic state but when a complex is formed the ligands destroy the degeneracy of these orbitals on the basis of crystal field theory. In the light of the above statements, choose the correct answer from the options given below:

Arrange the following ligands in the order of increasing field strength:
$H_2O$ $(I)$,$CO$ $(II)$,$NH_3$ $(III)$,$I^{-}$ $(IV)$,$F^{-}$ $(V)$

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