The vapour pressure of pure benzene and methy | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given that the mixture is equimolar,the mole fraction of benzene $(X_B)$ and methyl benzene $(X_M)$ in the liquid phase are both $0.5$.The partial

Vedclass · Accepted Answer

$23$

Vedclass · Answer

(C) Given that the mixture is equimolar,the mole fraction of benzene $(X_B)$ and methyl benzene $(X_M)$ in the liquid phase are both $0.5$.The partial vapour pressure of methyl benzene is $P_M = X_M 	imes P^{\circ}_M = 0.5 	imes 24 \ Torr = 12 \ Torr$.The partial vapour pressure of benzene is $P_B = X_B 	imes P^{\circ}_B = 0.5 	imes 80 \ Torr = 40 \ Torr$.The total vapour pressure is $P_{	ext{total}} = P_M + P_B = 12 \ Torr + 40 \ Torr = 52 \ Torr$.The mole fraction of methyl benzene in the vapour phase $(Y_M)$ is given by $Y_M = \frac{P_M}{P_{	ext{total}}}$.$Y_M = \frac{12}{52} \approx 0.2307$.Rounding to the nearest integer as requested,$Y_M \approx 23 	imes 10^{-2}$.

Similar Questions

At $298 \ K$,if the vapour pressure of pure liquids toluene,benzene,chloroform and dichloromethane are $60, 160, 200$ and $415 \ torr$ respectively,then which liquid has the highest boiling point?

When $18 \ g$ of glucose $(C_6H_{12}O_6)$ is added to $178.2 \ g$ of water,the vapour pressure of the aqueous solution at $100 \ ^\circ C$ is .......... $torr$.

$A$ mixture of ethyl alcohol and propyl alcohol has a vapour pressure of $290 \, mm$ at $300 \, K$. The vapour pressure of propyl alcohol is $200 \, mm$. If the mole fraction of ethyl alcohol is $0.6$,its vapour pressure (in $mm$) at the same temperature will be:

What is the vapor pressure of a solution containing a solid solute and a liquid solvent?

Vapour pressure of solvent is $17.5 \ mm \ Hg$ while that of dilute solution is $17.45 \ mm \ Hg$; the mole fraction of solvent is

Vedclass Test Series

Exam Paper Generator

Online Exam Module