The variation of potential V with distance x | vedclass

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Question

(C) The electric field $E$ is related to the potential $V$ by the relation $E = -\frac{dV}{dx}$,which is the negative of the slope of the $V-x$ graph.

Vedclass · Accepted Answer

$5$

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(C) The electric field $E$ is related to the potential $V$ by the relation $E = -\frac{dV}{dx}$,which is the negative of the slope of the $V-x$ graph.At $x = 13\,m$,the point lies on the line segment between $x = 12\,m$ and $x = 16\,m$.The coordinates of the endpoints of this segment are $(12, 30)$ and $(16, 10)$.The slope of this line segment is $	ext{slope} = \frac{V_2 - V_1}{x_2 - x_1} = \frac{10 - 30}{16 - 12} = \frac{-20}{4} = -5\,V/m$.Therefore,the electric field $E = -(	ext{slope}) = -(-5) = 5\,V/m$.

The variation of potential $V$ with distance $x$ from a fixed point is as shown in the figure. The electric field at $x = 13\,m$ is......$V/m$.

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